A piece of iron (400g) is heated in a flame and then dropped into a beaker containing 1000g of water. The orig? - flame iron on transfers
Might help if) you finish the question. But it looks like a problem of heat.
-Q (lost by iron) = q (acquired) by water
-Q (lost by iron) = mass x specific heat x temperature change
Lost by iron solution for q is Q-hold water for granted:
-Q (lost by iron) = mass of water (1000 g) x specific heat of water [4.184 J / (gx K)] x temperature change
and resolve to change the temperature. Moreover, the negative sign before Q is given as: q (lost) + Q (gained) = 0, so that Q (loss) = q (acquired).
You can use these ideas to everything you resolve to solve.
Flame Iron On Transfers A Piece Of Iron (400g) Is Heated In A Flame And Then Dropped Into A Beaker Containing 1000g Of Water. The Orig?
5:30 PM
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